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geniusboy [140]
3 years ago
7

ANSWER ASAP PLEASE Find the distance between the points (6, 5) and (4, 3). A) 2 B) 2 sqt2 C) 2sqrt3

Mathematics
1 answer:
rewona [7]3 years ago
6 0

Answer:

15

Step-by-step explanation:

dude this is like kindergarten things

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Six<br> PRODUCT Identities involving the trigonometric ratios.
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Defining relations for tangent, cotangent, secant, and cosecant in terms of sine and cosine

Step-by-step explanation:

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24.Jill has $800 and is spending $30 per week. Gill has $150 and is saving $20
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Jill and Gill will have the same amount of money in week 13, they will both have $410.
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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
The difference between a number divided by 3 and 4 is 20
Rzqust [24]
Set the number to x.

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Step-by-step explanation:

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