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3 years ago

What is 9/16 divided by 3/8 Please help.

Mathematics

1 answer:

ozzi3 years ago

5 0

Answer: 3/2

Step-by-step explanation:

Concept:

When doing division "[a]÷[b]", [a] is the dividend, [b] is the divisor.

Solve:

(9/16) / (3/8) ⇔ Given

(9/16) × (8/3) ⇔ Convert division into multiplication by using the reciprocal

of the divisor

(9×8) / (16×3) ⇔ Numerator multiply each other/ Denominator multiply each

other

72 / 48 ⇔ Multiplication

(3×24) / (2×24) ⇔ Factorize

3 / 2 ⇔ Simplify

Hope this helps!! :)

Please let me know if you have any questions

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Twice the difference of a number 2 and 5 is ?

alexandr1967 [171]

Answer:

n= 4.5

Step-by-step explanation:

The equation is:2(n-2)=5

Step 1- You need to do the parentheses.

The new equation is:

2n-4=5

Step 2-Next you add 4 to both sides of the equal sign.

The new equation is:

2n=9

Step 3- Now you divide by 2 into both sides and get the answer.

Answer:

n=4.5

8 0

3 years ago

-8 = -19 + C plz answer this

TiliK225 [7]

Answer:

c = 11

Step-by-step explanation:

-8 = -19 + 11

4 0

3 years ago

How do you determine the area under a curve in calculus using integrals or the limit definition of integrals?

RSB [31]

Answer:

Please check the explanation.

Step-by-step explanation:

Let us consider

$y = f(x)$

To find the area under the curve $y = f(x)$ between $x = a$ and $x = b$ , all we need is to integrate $y = f(x)$ between the limits of $a$ and $b$ .

For example, the area between the curve y = x² - 4 and the x-axis on an interval [2, -2] can be calculated as:

$A=\int _a^b|f\left(x\right)|dx$

= $\int _{-2}^2\left|x^2-4\right|dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=\int _{-2}^2x^2dx-\int _{-2}^24dx$

solving

$\int _{-2}^2x^2dx$

$\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=\left[\frac{x^{2+1}}{2+1}\right]^2_{-2}$

$=\left[\frac{x^3}{3}\right]^2_{-2}$

computing the boundaries

$=\frac{16}{3}$

Thus,

$\int _{-2}^2x^2dx=\frac{16}{3}$

similarly solving

$\int _{-2}^24dx$

$\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax$

$=\left[4x\right]^2_{-2}$

computing the boundaries

$=16$

Thus,

$\int _{-2}^24dx=16$

Therefore, the expression becomes

$A=\int _a^b|f\left(x\right)|dx=\int _{-2}^2x^2dx-\int _{-2}^24dx$

$=\frac{16}{3}-16$

$=-\frac{32}{3}$

$=-10.67$ square units

Thus, the area under a curve is -10.67 square units

The area is negative because it is below the x-axis. Please check the attached figure.

6 0

3 years ago

How do you answer this following equation “ the sum of two numbers is 33 , and the sum of 7 times the first number and 5 times t

nadya68 [22]

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