N / 2
400 / 2 = 200
200 / 2 = 100
100 / 2 = 50
50 / 2 = 25
25 / 2 = 12.5
Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.



b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
Answer:
5/6 (i think im not good at math soz)
-Mina
Step-by-step explanation:
Branily stop deleting my awnsers
<u><em>hi there user! Looks like your looking for help, so Mizuki came here to help you!</em></u>
the answer is:
<em>m is 2/3</em>
The whole work I did:
m + 4 ÷ 3 = 2
m + 4/3 = 2
m + 4/3 - 4/3 = 2 - 4/3
m = 6/3 - 4/3
m = 2/3
Anyways hope this helped! qwq