4.83 x 10^-3 can be re-written in standard form by moving the decimal point 3 units to the left: 0.00483.
Note: If you want to be mathematically correct, please write 10^(-3), not 10^-3. If the exponent is +, you don't need the parentheses.
From the Venn diagram: 15 players like Chemstrand, 17 players like Chemgrass, 13 players like both Chemstrand and Chemgrass while 10 players like neither Chemstrand nor Chemgrass.
The missing values in the frequency table are x - representing the number of players that like both Chemstrand and Chemgrass, y - representing the number of players that like Chemgrass but do not like Chemstrand and z - representing the number of players likes Chemstrand but do not like Chemgrass.
The number of players that like both Chemstrand and Chemgrass is 13. The number of players that like Chemgrass but do not like Chemstrand is 17. The number of players likes Chemstrand but do not like Chemgrass is 15.
Therefore, x = 13, y = 17 and z = 15
<u>The given options are:</u>
(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
(B)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the circumference of the circle will yield the area of the sector.
(C)the central angle measure of the sector multiplied by the area of the circle will yield the area of the sector.
(D)the central angle measure of the sector multiplied by the circumference of the circle will yield the area of the sector.
Answer:
(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
Step-by-step explanation:
The area of the shaded sector can be determined using the formula:



Therefore, the formula is:

Therefore, the formula is best explained by Option A.
1.29 is 6.45 divided by 5
Answer:
im not sure im really sorry
Step-by-step explanation:
im answering this because i have the same question