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s344n2d4d5 [400]
3 years ago
12

Please help i'm not doing good in math i will give you the crown

Mathematics
1 answer:
sp2606 [1]3 years ago
6 0

Answer:

B

Step-by-step explanation:

The format for quadrant 2 would be (-,+) and answer choice be fits that because it is(-3,2)

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Rudik [331]

Answer:

What do you mean?

Step-by-step explanation:

7 0
2 years ago
I need help with both please no links!
nlexa [21]

Answer:

The first one- 24, The second one-B

Step-by-step explanation:

The first one-Top corner=110, 110+46=156, 180-156=24

The other one-I have no clue how to explain it

4 0
3 years ago
HELP ASAP!!!!! SOMEONE HELP ME?!?!
Kitty [74]

Answer:

The first step when factoring any polynomial is to factor out the GCF. The GCF is the greatest common factor for all the terms of the polynomial. By factoring out the GCF first, the coefficients and constant term of the polynomial will be reduced.

4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!!!!!
viva [34]

Answer:

A: 5:1

B. 2:10

Step-by-step explanation:

Please mark brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

3 0
3 years ago
Unknown to a medical researcher, 6 out of 25 patients have a heart problem that will result in death if they receive the test dr
Fiesta28 [93]

Using the hypergeometric distribution, it is found that there is a 0.0002 = 0.02% probability that exactly 6 patients will die.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

The values of the parameters for this problem are:

N = 25, k = 6, n = 8.

The probability that exactly 6 patients will die is P(X = 6), hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 6) = h(6,25,8,6) = \frac{C_{6,6}C_{19,2}}{C_{25,8}} = 0.0002

0.0002 = 0.02% probability that exactly 6 patients will die.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

#SPJ1

8 0
2 years ago
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