Answer:
2 unit/time²
Step-by-step explanation:
Given the equation:
v(t) =t^2-3t
At interval ; 1, 4
V(1) = 1^2 - 3(1)
V(1) = 1 - 3
V(1) = - 2
At t = 4
V(4) = 4^2 - 3(4)
V(4) = 16 - 12
V(4) = 4
Average acceleration : (final - Initial Velocity) / change in time
Average acceleration = (4 - (-2)) ÷ (4 - 1)
Average acceleration = (4 + 2) / 3
Average acceleration = 6 /3
Average acceleration = 2
F(x) = (-x²+x+20) / (x+4)
-x²+x+20 | x+4
+x²+4x -x+5
\\\\ 5x+20
-5x-20
\\\\\\\\\
f(x) = (x+4)(-x+5) / (x+4)
f(x) = (-x+5)
The graph is a decreasing line, with origin from 5.
Pythagorean theorem
c2 = a2 + b2
71^2 = 43^2 + b2
5041 = 1849 + b2
3192 = b2
b = 56.5 which is answer choice d
The solution is negative.