Which is the best strategy to solve this problem?

Consider the equation 1.5x+4.5y=18. If we graph the equation, what is the

dlinn [17]

Answer:

M=-1/3

Y=-1/3x + 4

5 0

3 years ago

Can you help me<br>I don't really know this question very good so can you help me please

amid [387]

Answer:

1.92 miles

Step-by-step explanation:

she had walked 10 miles so that is where you start

Monday she had walked 2.38 so you subtract that from her total

Tuesday she had walked 2.4 so you subtract that from your new total

Wednesday she had walked 3.3 and you subtract that from the new total also

Thursday she had not walked anything so your remaining total is the amount she had walked on Friday

8 0

3 years ago

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

a)

The probability that both televisions work is: 0.42

b)

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

a)

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

b)

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

4 years ago

If I had 81.8*10^0,would my answer be 81.8

erastova [34]

Yes, it would still remain the same.

4 0

3 years ago

Read 2 more answers

What multiplies to 16 and adds to negative 12

Romashka-Z-Leto [24]

Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm

we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

0=x^2+12x+16
a=1
b=12
c=16

x= $\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}$
x= $\frac{-12+/- \sqrt{144-64 }}{2}$
x= $\frac{-12+/- \sqrt{80}}{2}$
x= $\frac{-12+/- 4\sqrt{5}}{2}$
x= $\frac{-6+/- 2\sqrt{5}$
x= $\frac{-6+ 2\sqrt{5}$ or $\frac{-6- 2\sqrt{5}$

aprox
x=-1.52786 or -10.4721

those are the numbers

the numbes are -1.52786 or -10.4721

6 0

3 years ago

Read 2 more answers