Enter the equation of the following using line in slope-intercept form.

A.CED.A Garnetta owned 2400 shares of Metropolitan Corporation at a price of $45.50. The stock split 4-for-3. How was Garnetta f

shtirl [24]

Garnetta will have 3,200 shares worth $ 34,125 each.

Given that Garnetta owned 2400 shares of Metropolitan Corporation at a price of $ 45.50, and the stock split 4-for-3, to determine how Garnetta was financially affected by the split the following calculation must be performed:

3 = 2400
4 = X
4 x 2400/3 = X
9600/3 = X
3200 = X
(2400 x 45.50) / 3200 = X
109200/3200 = X
34.125 = X

Therefore, Garnetta will have 3,200 shares worth $ 34,125 each.

Learn more in brainly.com/question/13981349

4 0

2 years ago

Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab

Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected, and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, $H_0$ : $\mu$ = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, $H_1$ : $\mu$ < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, X bar = sample mean = 738.44 hours

s = sample standard deviation = 38.2 hours

n = sample size = 50

So, test statistics = $\frac{738.44-750}{\frac{38.2}{\sqrt{50} } }$ ~ $t_4_9$

= -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0

3 years ago

What are the coordinates of the intersection of the diagonals of parallelogram LMNO, with vertices L(0,-3), M(-2,1), N(1,5), O(3

ArbitrLikvidat [17]

ANSWER

$\boxed {( \frac{1}{2} , 1)}$

EXPLANATION

The given parallelogram has vertices,

L(0,-3), M(-2,1), N(1,5), O(3,1).

The diagonals of the parallelogram bisect each other.

From the diagram, we can see that, the diagonals have coordinates L(0,-3),N(1,5)

and

M(-2,1),O(3,1).

The midpoint of any of the diagonals will give us the coordinates of intersection of the diagonals.

Recall the midpoint formula,

$(\frac{x_1+x_2}{2}, \frac{y_2+y_1}{2})$

Using L(0,-3),N(1,5) gives,

$(\frac{0+1}{2}, \frac{ - 3+5}{2})$

$(\frac{1}{2}, \frac{ 2}{2})$

$(\frac{1}{2}, 1)$

Or we could have also used,M(-2,1),O(3,1) to get,

$(\frac{-2+3}{2}, \frac{ 1+1}{2})$

$(\frac{ 1}{2}, \frac{ 2}{2})$

$(\frac{ 1}{2}, 1)$

The correct answer is C