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sergejj [24]
3 years ago
13

Sort the following functions from asymptotically smallest to asymptotically largest, indicating ties if there are any. You do no

t need to turn in proofs (in fact, please don't turn in proofs).
a. 4^2lgn
b. n
c. n^2.1
d. 2^lgn
Mathematics
1 answer:
Serhud [2]3 years ago
3 0

Answer:

b. n

d. 2^lgn

c. n^2.1

a. 4^2lgn

Step-by-step explanation:

Logarithm is a function of mathematics which is used to calculate inverse function of exponents. The asymptotically smallest function will be the one that has smallest or no exponents. The exponent function is calculated in reverse when log is applied. The function with highest exponents will be largest asymptotically.

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erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
8 0
3 years ago
Please help me asap!
netineya [11]

Answer:

Step-by-step explanation: I think it is c

5 0
3 years ago
Plz answer these i dont know them
Black_prince [1.1K]

Answer:

117, 55, 54, 77, 130, 7h + 5x, 14

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Write the expression as a polynomial, using the corresponding formula for special product: (−a–b)(−a–b)
Dmitriy789 [7]

Answer:

The Answer is: a^2 + 2ab + b^2

Step-by-step explanation:

Multiply the first factor resulting in the a squared, then the two inner factors resulting in ab + ab, finally the last term, resulting in b squared. Then combine terms:

(-a - b)(-a - b) =

a^2 + ab + ab + b^2 =

a^2 + 2ab + b^2

Hope this helps! Have an awesome day! :-)

5 0
4 years ago
Read 2 more answers
Using the Fundamental Theorem of Algebra. Complete the following exercises. Show your work.
svp [43]

Answer:

A) - Quartic polynomial

- has four roots

- roots are; f(x) = (x + 5i)(x - 5i)(x + 2)(x - 2)

B) - Cubic polynomial

- has 3 roots

- roots are; f(x) = (x - 5)²(x + 5)

Step-by-step explanation:

A) f(x) = x⁴ + 21x² − 100

The highest power in this polynomial is 4 and thus, it is called a quartic polynomial. This means that it will have 4 roots.

Factorizing this polynomial gives;

f(x) = (x² + 25)(x² - 4)

Equating to zero, we can find the roots. Thus, the roots are;

x = 5i

x = -5i

x = 2

x = -2

Thus, the completely factorized polynomial is;

f(x) = (x + 5i)(x - 5i)(x + 2)(x - 2)

B) f(x) = x³ − 5x² − 25x + 125

The highest power in this polynomial is 3. It is therefore a cubic polynomial with 3 roots.

Factorizing this polynomial gives;

f(x) = (x² - 25)(x - 5)

Equating to zero and Factorizing gives;

x = 5

x = -5

x = 5

Thus, completely factorized with the roots is;

f(x) = (x - 5)²(x + 5)

4 0
3 years ago
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