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anzhelika [568]
3 years ago
15

WHAT IS THE ANSWER!!!!!!!!!

Mathematics
1 answer:
lesya [120]3 years ago
3 0

Multiply each side of the given equation by <span>ax−2</span> (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:

<span><span><span><span>24 x ^2 </span>+ 25x </span>− 47 </span>= <span><span><span>(<span><span>−8x</span>−3</span>)</span><span>(<span>ax−2</span>)</span></span>−53</span></span>

You should then multiply <span>(<span><span>−8x</span>−3</span>)</span> and <span>(<span>ax−2</span>)</span> using FOIL.

<span><span><span><span>24 x ^2 </span>+ 25x </span>− 47</span>= <span><span><span><span><span>−<span>8ax^2 </span></span>− <span>3ax </span></span>+ 16x </span>+ 6 </span>− 53</span></span>

Then, reduce on the right side of the equation

<span><span><span><span>24 x ^2 </span>+ 25x </span>− 47</span>= (<span><span>−<span>8x </span></span>− <span>3(ax - 2) - 53</span></span></span>

Since the coefficients of the x^2-term have to be equal on both sides of the equation, <span><span>−8a</span>=24</span>, or <span>a=−3</span>.

Your answer would be <span>B</span>
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A batch of 40 semiconductor chips is inspected by choosing a sample of 5 chips. Assume 10 of the chips do not conform to custome
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Answer:

a) 658008 samples

b) 274050 samples

c) 515502 samples

Step-by-step explanation:

a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.

So, the number of samples = ⁴⁰C₅ = 658008 samples

b) How many samples of 5 contain exactly one nonconforming chip?

There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways

¹⁰C₁ = 10 ways

then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways

³⁰C₄ = 27405 ways

So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples

c) How many samples of 5 contain at least one nonconforming chip?

The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)

Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples

Total number of samples = 658008

The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples

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Hope this helps!
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HELP PLEASE 21 POINTS PLEASE HELP ME!!!! &lt;3
Anna007 [38]

1)

n         1          2         3           4         5         6

f(n)    1033    932     831      730     629     528

First term (a₁):  <u>1033 </u>          Common difference (d): <u>-101 </u>

Explicit rule:  a_{n} = 1134 - 101n    Recursive rule: a_{n} = a_{n-1} - 101

a_{n} = a_{1} + d(n - 1)

a_{n} = 1033 - 101(n - 1)

a_{n} = 1033 - 101n + 101

a_{n} = 1134 - 101n

***********************************************************************************

2)

n         1          2         3           4         5         6

f(n)   -39      -29       -19        -9          9        19

First term (a₁):  <u> -39  </u>          Common difference (d): <u> +10  </u>

Explicit rule:  a_{n} = -49 + 10n    Recursive rule: a_{n} = a_{n-1} + 10

a_{n} = a_{1} + d(n - 1)

a_{n} = -39 + 10(n - 1)

a_{n} = -39 + 10n - 10

a_{n} = -49 + 10n

***********************************************************************************

3)

n         1          2         3           4         5         6

f(n)   3.75      2.5     1.25        0      -1.25     -2.5

First term (a₁):  <u> 3.75  </u>          Common difference (d): <u> -1.25  </u>

Explicit rule:  a_{n} = 5 - 1.25n    Recursive rule: a_{n} = a_{n-1} - 1.25

a_{n} = a_{1} + d(n - 1)

a_{n} = 3.75 - 1.25(n - 1)

a_{n} = 3.75 - 1.25n + 1.25

a_{n} = 5 - 1.25n


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4 years ago
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