We are given first equation y=
x+11.
Second equation is -3x + 7y = 13.
Part A: We need to convert that second equation in slope-intercept form y=mx+b.
In order to convert it in slope-intercept form, we need to isolate it for y.
-3x + 7y = 13
Adding 3x on both sides, we get
-3x+3x + 7y = 3x+13
7y = 3x +13.
Dividing both sides by 7, we get
7y/7 = 3x/7 +13/7.
<h3>y= 3/7 x + 13/7.</h3>
Slope for first equation y=3/7 x +11 is 3/7 and slope of second equation y= 3/7 x + 13/7 is also 3/7.
Slopes are same for both equations.
<h3>Part B: Therefore, lines are parallel due to equal slopes.</h3>
Hey there !!
=) length of rectangle = 76w
=) width of rectangle = w
we know that perimeter = 2(l+b)
= 2(76w+w)
The point-slope form:

We have the point (-1, 7) and the slope m = 2. Substitute:

Less than 90°. All acute angles in a triangle are less than 90°.
Answer:
15/56x^(-4/7) + 32x^3 + 6.
Step-by-step explanation:
Using the rule for algebraic differentiation:
If y = ax^n, dy/dx = anx^(n-1).
So :
If y = 5/8x^3/7 + 8x^4 + 6x - 9
dy/dx = 5/8* 3/7 x^(3/7-1) + 8*4 x^(4-1) + 6x(1-1)
= 15/56x^(-4/7) + 32x^3 + 6.