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Rufina [12.5K]
3 years ago
7

Xue Ying had 143 more sweets than Joanne.After Joanne gave away 22 sweets, Xue Ying had 6 times as many sweets as Joanne. How ma

ny sweets did Joanne have in the end?
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Answer:

In the end Joanne had 55 sweets.

Step-by-step explanation:

Let the number of sweets that Xue Ying had be y and let the number of sweets Joanne had be x.

It is given that Xue Ying had 143 more sweets than Joanne. We can write this information as an equation.

               y = x + 143.

It is also given that Joanne gave away 22 of her sweets and after that Xue Ying had 6 times as many more sweets. We can write this as an equation.

             y = 6(x - 22) = 6x - 132.

Therefore we can equate the two equations and solve for x.

                 x + 143  = 6x  - 132

                5x  = 275

        ∴       x =  \frac{275}{5}  = 55 sweets.

Therefore in the end Joanne had 55 sweets.                        

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