In triangle ABC, angle A= 38 degrees 40', a=16, b=20, and angle B is an obtuse angle. What is the measure of angle C to the near
1 answer:
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Answer:
<u>Step-by-step explanation:</u>
y = A cos (Bx - C) + D
- A (amplitude) = max - D
- B = Period/2π ---> Period is the distance from max to next max
- C = B · Phase Shift ---> Phase shift is distance from y-axis to max
- D (vertical shift) = (max + min)/2
D = (max + min)/2 = (3 - 11)/3 = -4
A = max - D = 3 - (-4) = 7
Period = 9π/4 - π/4 = 8π/4 = 2π
B = Period/2π = 2π/2π = 1
Phase Shift = π/4 - 0 = π/4
C = B · Phase Shift = 1 · π/4 = π/4
Equation:
y = 7 cos (1·x - π/4) + (-4)
Answer:
The total surface area is 896
Step-by-step explanation:
<em>The square pyramid is a solid with square base and symmetric 4 triangular faces.</em>
Given that the square base is 14 m and height is 24 m.
The apex of pyramid, center of square and center of any edge of square make a right angled triangle.
Let that height if triangular face be "x".
by pythagoras theorm ,
x = 25 m
the area of square base is
the area of each triangular side is <em></em>
such are 4 triangles, thus
Thus the total surface area is 196 + 700 = 896
