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prohojiy [21]
3 years ago
7

Someone help me please

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
Would it be a ratio, if it is it would most practically be 10:40 and if in simplest form it would be 1:4 or just you photo math


 
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Two cylinders are similar. The radius of cylinder A is 5.6 inches. The radius of cylinder B is 1.4 inches. If the height of cyli
natita [175]
The answer is 16 inches.

Let r be a radius and h be a height of a cylinder
Since the cylinders are similar, then the ratio between their radiuses is equal to the ratio of their heights:
r1 : r2 = h1 : h2

Cylinder A:
r1 = 5.6 in
h1 = ?

Cylinder B:
r2 = 1.4 in
h2 = 4 in

5.6 : 1.4 = h1 : 4
h1 = 4 * 5.6 : 1.4
h1 = 16 inches
7 0
3 years ago
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Is my answer correct ??
serious [3.7K]

Answer:

it is correct indeed,

Step-by-step explanation:

quick google search says so

3 0
3 years ago
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Solve 10e^2x - 5 =23^x for x.
yawa3891 [41]

10e^{2x}-5=23e^x\qquad\text{subtract}\ 23e^x\ \text{from both sides}\\\\10e^{2x}-23e^x-5=0\\\\10(e^x)^2-23(e^x)-5=0\\\\\text{substitution:}\ e^x=t > 0\\\\10t^2-23t-5=0\\\\10t^2-25t+2t-5=0\\\\5t(2t-5)+1(2t-5)=0\\\\(2t-5)(5t+1)=0\iff2t-5=0\ \vee\ 5t+1=0\\\\2t=5\ \vee\ 5t=-1\\\\t=\dfrac{5}{2} > 0\ \vee\ t=-\dfrac{1}{5} < 0\\\\\text{therefore}\ e^x=\dfrac{5}{2}\to\ln e^x=\ln\left(\dfrac{5}{2}\right)\\\\\boxed{x=\ln\left(\dfrac{5}{2}\right)}

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3 years ago
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0.5; MATH PROBLEM HERE!!,,,,,,,,,
spayn [35]
It might be f but I’m getting a positive 6 instead of a negative
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Solve. <br><br> 6x − 8 = −44 <br><br> x =
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I think the best value for x is -9 because 6 x -9 = 54, minus 8 equals -44.
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