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andre [41]
3 years ago
13

Graph y< -2/3x +6 Please help ASAP

Mathematics
1 answer:
Fed [463]3 years ago
4 0
Your answer would be the one on the bottom left. I recommend the app “Mathaway” that will help you graph problems like this.
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If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func
nadya68 [22]

Answer:

a) C(1,000)=288,491.11 $

b) c(1,000)=288.49 $/u

c) dC/dx(1,000)=349.74 $/u

d) x=100 u

e) c=220 $/u

Step-by-step explanation:

(a) Find the total cost at a production level of 1000 units.

C(x) = 2,000 + 160x + 4x^{3/2}\\\\C(1,000)=2,000 + 160(1,000) + 4(1,000)^{3/2}\\\\C(1,000)=2,000+160,000+126,491.11= 288,491.11

(b) Find the average cost at a production level of 1000 units.

c(x)=C(x)/x\\\\c(1,000)=C(1,000)/1,000=288,491.11/1,000=288.49

(c) Find the marginal cost at a production level of 1000 units.

\frac{dC}{dx} =0+160+4*(3/2)x^{3/2-1}=160+6x^{1/2}\\\\dC/dx|_{1,000}=160+6*(1,000)^{1/2}=160+189.74=349.74

(d) Find the production level that will minimize the average cost.

c=2,000x^{-1}+160+4x^{1/2}\\\\dc/dx=2,000(-1)x^{-2}+0+4(1/2)x^{-1/2}=0\\\\-2,000x^{-2}+2x^{-1/2}=0\\\\2x^{-1/2}=2,000x^{-2}\\\\x^{-1/2+2}=1,000\\\\x^{3/2}=1,000\\\\x=1,000^{2/3}=100

(e) What is the minimum average cost?

c(x) = 2,000/x + 160 + 4x^{1/2}\\\\C(100)=2,000/100 + 160 + 4(100)^{1/2}=20+160+40=220

5 0
3 years ago
2.
Sphinxa [80]
It's B cause it's open upwards.
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3 years ago
Given the system of equations, what is the solution?
snow_tiger [21]

Answer:

Its b trust me

Step-by-step explanation:

I did the work lol

5 0
2 years ago
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What fraction is equal to the decimal 0.4?
Sholpan [36]
<span>Step 1: 0.4 = 4⁄10</span>
<span>Step 2: Simplify 4⁄10 = 2⁄5</span>             
4 0
3 years ago
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If n(A) =15 n (B) = 9 n(A∩B) =4 <br> find n(A U B)
Xelga [282]

Answer:

20

Step-by-step explanation:

n(A) only =15-4=11

n(B) only=9-4=5

n(A n B)=4

n(A U B)=11+5+4=20

5 0
3 years ago
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