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rewona [7]
3 years ago
9

Describe the graph of the function y= square root of x-7+3

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0

Answer:

Step-by-step explanation:

y=sqrt(x-7)+3 is a transformed from the parent function y=sqrt(x) by the following:

right 7 units

up 3 units

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Angie’s Bake Shop makes birthday chocolate chip cookies that cost $2 each. Angie expects that 10% of the cookies will crack and
wlad13 [49]

Answer:

Step-by-step explanation:

the value of the cookies can be 1.20

8 0
3 years ago
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For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at
GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}

Now, let's add the components of the same direction:

\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}

To find the resultant bearing (theta), we can use the formula below:

\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0
1 year ago
A pound of cherries is normally $5.00. Today there is a 20% discount. What is the sale price
Kruka [31]
The Answer Is $4.00
Hope This Helps!

6 0
3 years ago
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Use a table of values with at least 5 values to graph the following function:
34kurt

The given expression :

y=(\frac{1}{2})^x

For coordinates:

put x = 0 then :

\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}

Coordinate : (x, y) = (0, 1)

Put x= 1 and simplify :

\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

4 0
1 year ago
Factor completely. 8y^2 - 26y + 15 (4y - 3)(2y - 5) (2y - 3)(4y - 5) 2(2y - 3)(2y - 5)
Zarrin [17]

8y^2 - 26y + 15

= (4y - 3)(2y - 5)

Hope it helps.

7 0
3 years ago
Read 2 more answers
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