According to the information in the table, who is the fastest typist?
2 answers:
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Problem 13
If we want to multiply (x^3-3x^2+2x) with (x^3-2x^2+x), then we can set up a diagram shown below. The terms are along the outside. The stuff inside is the result of multiplying each pair of outer terms.
- Example: x^3 times x^3 = x^6 in the top left corner
- Another example: 2x times x = 2x^2 in the bottom right corner.
This is known as the box method to keep track of all the terms multiplied.
Once the table is filled out, we add up each term inside the boxes. Combine like terms if possible. Notice that I color-coded the like terms (eg: the x^3 terms are in green boxes).
The final answer is x^6 - 5x^5 + 9x^4 - 7x^3 + 2x^2
Solution
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the formula for slope
STEP 2: Pick two points
STEP 3: Find the unit price per cup
Since 4 cups cost $5, one cup will cost
Therefore, the answer is $1.25
When x =170, y =10, when x = 187, y = 1, when x = 204, y = 12, when x = 221, y = 13, when x = 238, y = 14, when x = 255, y = 15, when x = 272, y = 16, when x = 289, y = 17, when x = 306, y = 18, when x = 323, y = 19, when x = 340, y = 20,
Step-by-step explanation:
Step 1; Assume y is the gallons in the tank while x is the range of the car. We need to determine the equation relating the y to the x values in the given coordinates. x is the dependent value whereas y is the independent value i.e. the value of x depends on the value of y.
Step 2; As y increases, x also increases. For every extra gallon in the tank, the car can go another 17 miles. So with y as the amount of gas in the tank in gallons and x as the range of vehicle, we get;
x = 17y, this represents the relation between x and y.
To find the gallons in the tank, y = ,
For x = 170, y = = 10,
Similarly equating the values we get that when x = 187, y = 11,
when x = 204, y = 12,
when x = 221, y = 13,
when x = 238, y = 14,
when x = 255, y = 15,
when x = 272, y = 16,
when x = 289, y = 17,
when x = 306, y = 18,
when x = 323, y = 19,
when x = 340, y = 20,