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Naily [24]
2 years ago
9

An animal park has lions,tiger an zebras.2/5 of the animals are lions and 3/10 of the animals are zebras. what percentage are ti

gers?​
Mathematics
1 answer:
maksim [4K]2 years ago
4 0

Answer:

3/10

Step-by-step explanation:

You have to make them the same fraction.

2/5 = 4/10

3/10 =3/10

3/10 + 4/10 = 7/10

10/10 - 10/10 =3/10

3/10 is the amount of tigers.

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Svetach [21]
Divide by the coefficient of x.
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Mr Dominguez spends three weeks training for a marathon. Every day he runs 1/2 mile more than the day before. If the first day h
barxatty [35]
Answer: 16 miles


Explanation:
I believe it would be 16 miles, if he starts off at 6 miles on day one and goes up 1/2 mile every day, he would be up a mile every other day, basically on day 3 he would be at 7 and day 5 at 8 miles, if the pattern continues he would be at 16 miles by day 21.
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3 years ago
PLS HELP ITS URGENT!
love history [14]

Answer:

the slope is 3

Step-by-step explanation:

8 0
2 years ago
It says to place points on them but i still don't get it. help please.
xxTIMURxx [149]

Answer: A'=(1, 3); B'=(-3, 4);C'=(3, 0); D'=(-2, 5)

You can check the PNG attached as well.

Step-by-step explanation:

You need to represent the symmetry of every given points respet to the line

y = 2

In that case, the line beeing paralell to the x- axis, x- value of the symmetry is the same of the given point and y = 2 is the middle between both points.

Point A(1, 1)

x_{A} = 1\\ x_{A'} = 1 \\\\\frac{y_{A} +y_{A'} }{2} =2\\y_{A'} = 4 - y_{A} = 4 - 1 = 3

Point B(-3, 0)

x_{B} = 1\\ x_{B'} = 1 \\\\\frac{y_{B} +y_{B'} }{2} =2\\y_{B'} = 4 - y_{B} = 4 - 0 = 4

Point C(3, 4)

x_{C} = 1\\ x_{C'} = 1 \\\\\frac{y_{C} +y_{C'} }{2} =2\\y_{C'} = 4 - y_{C} = 4 - 4 = 0

Point D(-2, -1)

x_{D} = 1\\ x_{D'} = 1 \\\\\frac{y_{D} +y_{D'} }{2} =2\\y_{D'} = 4 - y_{D} = 4 - (-1) = 4 + 1 = 5

4 0
3 years ago
The Wind Mountain excavation site in New Mexico is an important archaeological location of the ancient Native American Anasazi c
timurjin [86]

Answer:

a) 28

b)

Class Limits  Class Boundaries   Midpoint    f      Rf         Cf

10 - 37            9.5-37.5                   23.5            7     0.096     7      

38 - 65           37.5-65.5                 51.5           25    0.342     32    

66 - 93           65.5-93.5                 79.5          26    0.356     58    

94 -  121        93.5-121.5                   107.5         9     0.123       67    

122 - 149      121.5-149.5                  135.5         5      0.068     72  

150 - 177       149.5-177.5                  163.5        0         0.0      72    

178 - 205       177.5-20.5                  191.5         1       0.014      73  

Total                                                                  73          1.0    

c)

The histogram is in attached file.

Step-by-step explanation:

a)

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx
5 0
3 years ago
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