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4 years ago

Name the similar triangles

Mathematics

1 answer:

Setler79 [48]4 years ago

8 0

Answer:

I believe the answer is the second one but take precaution i haven´t done them in a few years so be careful.

Step-by-step explanation:

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Multiply

Cloud [144]

Answer:

12 x^4 + 18 x^3 - 9 x^2 thus D is the correct answer.

Step-by-step explanation:

Expand the following:

3 x^2 (4 x^2 + 6 x - 3)

3 x^2 (4 x^2 + 6 x - 3) = 3 x^2 (4 x^2) + 3 x^2 (6 x) + 3 x^2 (-3):

3 4 x^2 x^2 + 3 6 x^2 x - 3 3 x^2

3 (-3) = -9:

3 4 x^2 x^2 + 3 6 x^2 x + -9 x^2

3 x^2×6 x = 3 x^(2 + 1)×6:

3 4 x^2 x^2 + 3×6 x^(2 + 1) - 9 x^2

2 + 1 = 3:

3 4 x^2 x^2 + 3 6 x^3 - 9 x^2

3×6 = 18:

3 4 x^2 x^2 + 18 x^3 - 9 x^2

3 x^2×4 x^2 = 3 x^4×4:

3×4 x^4 + 18 x^3 - 9 x^2

3×4 = 12:

Answer: 12 x^4 + 18 x^3 - 9 x^2

6 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

4 years ago

Somebody help me I’m struggling

blondinia [14]

Answer:

A. $ (5 + 2x), B. = $ 305

Step-by-step explanation:

x miles

A. cost for x miles = 5 + 2x ($)

B. cost for 150 miles = 5 + 2*150 =305 ($)

7 0

3 years ago

Read 2 more answers

I need help with this

Iteru [2.4K]

You will divide 50 by 10 to get 5. Then multiply 5 by 50 to get 250

3 0

3 years ago

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Solve by graphingggggggg

olga_2 [115]

Answer:

Y can't i see the pic

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers