A rhombus has four equal sides. If the perimeter of this rhombus is 164, then the length of one side is 164/4, or 41.
Draw this rhombus. Label all four sides with "41." Label the longer diagonal 80 and the half length of that diagonal 40. You will see inside the rhombus four congruent triangles with hypotenuse 41, leg 10 and unknown height. Thus, this unknown height is found by solving x^2 + 40^2 = 41^2, and x^2=9, so that the length of the shorter diagonal is 2(2) = 18 (answer).
Answer:
the answer is 8. just think of it as subtraction. subtract +6 from +14. then you get the answer for +14+-6.
Answer:
A 28 because 7 times four
Step-by-step explanation:
You first need to make sure the denominators are equal, then when they are, you can add/subtract the numerators. Then you can place the result over the common denominator.
I hope this helps! :)
Answer:
what is the question ? but i dont know ans
