Answer:
21. 4
Step-by-step explanation:
2*3=6
4*6=24
24/6=4
what is a three band stretches
Answer:-4
Step-by-step explanation:
Answer:
11. s = 14
12. k = 24
Step-by-step explanation:
There are two "special" right triangles that show up in trig and geometry problems.
The isosceles right triangle has angles of 45°-45°-90°, and side length ratios 1 : 1 : √2.
The half-equilateral triangle has angles of 30°-60°-90°, and side length ratios 1 : √3 : 2.
You will do yourself a favor if you remember and learn to recognize these triangles.
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<h3>11.)</h3>
The hypotenuse of the isosceles right triangle is 14√2. This tells you the basic ratio has been multiplied by 14. The side length is ...
s = 14
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<h3>12.)</h3>
The half-equilateral triangle has middle-length side 12√3. This means the basic ratio has been multiplied by 12. The triangle short side is 12, and the long side is twice that:
k = 24
Answer:
a. 0.9
b. 0.024
c. 0.06
d. 0.2
e. 0.336
Step-by-step explanation:
Since A, B and C are mutually exclusive then P (A U B U C)=P(A)+P(B)+P(C) and P(A∩B∩C)=P(A)*P(B)*P(C).
a.
P (A U B U C)=P(A)+P(B)+P(C)
P (A U B U C)=0.2+0.3+0.4=0.9
b.
P(A∩B∩C)=P(A)*P(B)*P(C)
P(A∩B∩C)=0.2*0.3*0.4=0.024
c.
P(A∩B)=P(A)*P(B)
P(A∩B)=0.2*0.3=0.06
d.
P[(AUB)∩C]=P(AUB)*P(C)
P(AUB)=P(A)+P(B)=0.2+0.3=0.5
P[(AUB)∩C]=0.5*0.4=0.20
e.
P(A')=1-P(A)=1-0.2=0.8
P(B')=1-P(B)=1-0.3=0.7
P(C')=1-P(C)=1-0.4=0.6
P(A'∩B'∩ C')=P(A')*P(B')*P(C')
P(A'∩B'∩ C')=0.8*0.7*0.6=0.336
Consider plane A with respect to B,
initial relative Altitude 
relative rate of altitude(speed) $r_{a,b}= 55.75-35.5=20.25$
To get at same altitude, they'll take same time, and their relative height will be $0$ So,
$H_{a,b}=h_{a,b}+r_{a,b}t$
$0=-972+20.25t$
$t=48$
and altitude will be, $3028+55.75\cdot 48=5704$