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horrorfan [7]
4 years ago
6

What is an equation in slope-intercept form for the line that passes through the points (1, -3) and (3, 1)?

Mathematics
1 answer:
tensa zangetsu [6.8K]4 years ago
8 0
First we need to find the slope: 

Slope formula=\frac{y2-y1}{x2-x1}

Plug in your given values from the coordinate 
Slope =\frac{1-(-3)}{3-1}

When we have 2 "-"'s together they turn into a + sign so we add. 
Slope =\frac{1+3=4}{3-1=2}
Slope =\frac{4}{2}

Simplify (in this case divide) the slope: 
Slope =2

 slope-intercept form is: 
y=mx+b 
Where m=slope
b=y-intercept

So far we have:
y=2x+b 

To find b all we have to do is pick any given coordinate and plug it in: 
I chose (3,1) 

so we plug that in the equation
1=6+b 
 
Now solve for b:
1=6+b
subtract 6 from both sides 
b=-5  

Final answer: 
y=2x-5 (D) 
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21. 4

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Answer:

  11. s = 14

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Step-by-step explanation:

There are two "special" right triangles that show up in trig and geometry problems.

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4 0
3 years ago
If A, B, and C are mutually exclusive events with P(A) 0.2, P(B): 0.3, and P(C) 0.4, determine the following probabilities:
Lesechka [4]

Answer:

a. 0.9

b. 0.024

c. 0.06

d. 0.2

e. 0.336

Step-by-step explanation:

Since A, B and C are mutually exclusive then P (A U B U C)=P(A)+P(B)+P(C) and P(A∩B∩C)=P(A)*P(B)*P(C).

a.

P (A U B U C)=P(A)+P(B)+P(C)

P (A U B U C)=0.2+0.3+0.4=0.9

b.

P(A∩B∩C)=P(A)*P(B)*P(C)

P(A∩B∩C)=0.2*0.3*0.4=0.024

c.

P(A∩B)=P(A)*P(B)

P(A∩B)=0.2*0.3=0.06

d.

P[(AUB)∩C]=P(AUB)*P(C)

P(AUB)=P(A)+P(B)=0.2+0.3=0.5

P[(AUB)∩C]=0.5*0.4=0.20

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P(A'∩B'∩ C')=P(A')*P(B')*P(C')

P(A'∩B'∩ C')=0.8*0.7*0.6=0.336

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An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 3028 feet and Plane B is at an altitude
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Consider plane A with respect to B,

initial relative Altitude h_{a, b}=h_a-h_b=-972

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$H_{a,b}=h_{a,b}+r_{a,b}t$

$0=-972+20.25t$

$t=48$

and altitude will be, $3028+55.75\cdot 48=5704$

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