Answer:
Let x = the third side
In a triangle, the sum of any 2 sides must be larger than the third side.
I believe this is called the triangle inequality theorem.
We can construct 3 inequalities to obtain the range of values for the third side.
(Inequality #1) 12 + 4 > x
16 > x
(Inequality#2) 12 + x > 4
x > -8 (we can discard this ... we know all sides will be positive)
(Inequality #3) 4 + x > 12
x > 8
So when we combine these together,
8 < x < 16
X (the third side) must be a number between 8 and 16. but not including 8 and 16
Answer: x = 131
Reasoning: Alternate interior angle theorem
The angles shown are inside the parallel lines, so they are interior angles. They are also considered alternate angles because they are on alternating sides of the transversal cut. Alternate interior angles are congruent when we have parallel lines like this.
Answer:
12
Step-by-step explanation:
A = ½(b1 + b2)h
A = (3 + 5)(3)/2
A = 12
Answer:
5/7
Step-by-step explanation:
B
Answer:
Hey!
Your answer is 44!
Step-by-step explanation:
Here's how...
x+(x+2)+(x+4)+(x+6)+(x+8)=200
5x+20=200 (minus 20 on both sides to get 5x by itself)
5x=180 (divide both sides by 5 to get just x)
x=36
5th number - x+8=36+8=44 (simple substitution and addition)
I HOPE THIS HELPS!
