3 years ago

What must be the value of x so that lines a and b are parallel lines cut by transversal f?

Mathematics

2 answers:

ExtremeBDS [4]3 years ago

5 0

we know that

if the lines a and b are parallel lines cut by transversal f

then

$(6x-36)=96$ --------> by alternate exterior angles

solve for x

$(6x-36)=96\\ 6x=96+36\\6x=132\\x=(132/6)\\x=22\ degrees$

therefore

<u>the answer is</u>

the value of x is $22\ degrees$

chubhunter [2.5K]3 years ago

4 0

The answer is 22 i did it on ed
and i got it correct

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