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KonstantinChe [14]
3 years ago
5

Jacie is serving steak and chicken she wants to have at least 20 pounds of meat. Steak is $8 per pound and chicken is $4 per pou

nd . Jacie wants to spend at most 120 dollarss on meat
Mathematics
2 answers:
Nady [450]3 years ago
7 0

Answer:

She can get 10 pounds of steak and 10 pounds of chicken.

Step-by-step explanation:

As Jacie wants to have at least 20 pounds of meat, you can write the following  equation:

x+y=20, where

x refers to the pounds of steak

y refers to the pounds of chicken

Also, since the statement indicate that the steak is $8 per pound and chicken is $4 per pound and Jacie wants to spend at most 120 dollars on meat, you can write the following equation:

8x+4y=120

So, you have the following equations:

x+y=20 (1)

8x+4y=120 (2)

Now, you can solve for x in (1):

x=20-y (3)

Then, you can replace (3) in (2) and solve for y:

8(20-y)+4y=120

160-8y+4y=120

160-120=8y-4y

40=4y

y=40/4

y=10

Finally, you can relace the value of y in (3) to find x:

x=20-y

x=20-10

x=10

According to this, the answer is that she can get 10 pounds of steak and 10 pounds of chicken.

amm18123 years ago
3 0

Answer:

10 pounds of chicken and 10 pounds of steak

Step-by-step explanation:

If steak is $8 then you can get 10 for 10x8=80

If chicken is $4 then you can get 10 of that aswell for 10x4=40 and 80+40=120.

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Answer:

(-2,21)

Step-by-step explanation:

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8 days ago means that x-coordinate -8 represents this day. Count 8 units to the left and find that when x = -8, y = 24 minutes.

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y=\dfrac{24+18}{2}=\dfrac{42}{2}=21,

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3 years ago
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Softa [21]

Answer:

Step-by-step explanation:

7) The formula for determining the area of a parallelogram is expressed as

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Given:

Base length of triangle = 10 units

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5 0
3 years ago
A survey was done that asked people to indicate whether they preferred to swim in a pool or in an ocean. The results are shown i
posledela
Given:
                                 Pool swimming        Ocean swimming    Total
Age 30 and younger             228                         54                 282
Over 30 years old                142                        185                 327
total                                    370                        239                609

Frequencies:
                                Pool swimming        Ocean swimming    Total
Age 30 and younger     228/609 = 0.37         54/609 = 0.09       282/609 = 0.46
Over 30 years old        142/609 = 0.23       185/609 = 0.30       327/609 = 0.54
<span>total                           370/609 = 0.61       239/609 = 0.39       609/609 = 1.00</span>

<span>The relative frequency (rounded to the nearest hundredth) of a person over 30 years old who prefers to swim in the ocean is 0.30</span>    
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3 years ago
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