-i is the answer as the remainder of 30/4 is 3 which is i^3
1.)Convert Into Equation: -280=2x-53.6
2.)Simplify: -226.4=2x
3.)Isolate X: x=-113.2
X=-113.2
The question did not show the original vertices of A, B, and C.
Generally, for a triangle ABC that is dilated by a scale factor of four to form triangle A'B'C', the coordinates of vertices A', B', C' are:
For A(x, y)
The coordinate of vertex A' will be A' (4x, 4y)
For B(x, y)
The coordinate of vertex B' will be B' (4x, 4y)
For C(x, y)
The coordinate of vertec C' will be C' (4x, 4y)