Where do you guys watch free anime
2 answers:
You might be interested in
Answer:
The correct answer is x^np (1-p)^n-1
Step-by-step explanation:
See the picture attached
Hello,
x,y,z∈ IN
==>
x∈{35,36,37}
y∈{47,48,49}
z∈{141,144,147}
We must go futher:
if x=35 then y=4*35/3=46.666 not good , not whole
if x=36 then y=4*36/3=48 ok
if x=37 then y=37*4/3=49.333.. not good
So there is only one solution (36,48,144) for (x,y,z)
No problem with z for z=3/1*4/3*x=4x ==>whole.
x,y,z∈ IN
x∈{35,36,37}
y∈{47,48,49}
z∈{141,144,147}
We must go futher:
if x=35 then y=4*35/3=46.666 not good , not whole
if x=36 then y=4*36/3=48 ok
if x=37 then y=37*4/3=49.333.. not good
So there is only one solution (36,48,144) for (x,y,z)
No problem with z for z=3/1*4/3*x=4x ==>whole.