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Svet_ta [14]
3 years ago
9

1.56 times 48 equals How do you get the answer

Mathematics
1 answer:
spin [16.1K]3 years ago
5 0

Answer:

74.88

Step-by-step explanation:

1.56x48=74.88

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60 POINTS! (Reported if incomplete/absent)
GuDViN [60]

Answer:

- The neighbor that has the most amount of fence to put up is: Neighbor A.

- The neighbor that has the least amount of fence to put up is: Neighbor C.

Step-by-step explanation:

To calculate the amount of fence that Neighbor A has to put up, you need to add the following distances:

Convert yards to feet (Remember that :

To calculate the amount of fence that Neighbor B has to put up, you need to use the formula for calculate the circumference of a circle:

Where r is the radius.

In this case, the radius is:

Substituting, you get:

To calculate the amount of fence that Neighbor C has to put up, you need to add the following distances:

Therefore, the neighbor that has the most amount of fence to put up is: Neighbor A.

The neighbor that has the least amount of fence to put up is: Neighbor C.

hope this helps btw i just copy and pasted this so its not my work

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3 years ago
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Show that sinxtanx=1-cos^2x/cosx
yawa3891 [41]
LHS: = \sin x \tan x =  \frac{\sin x \sin x }{\cos x} =  \frac{\sin^2 x}{\cos x} (using \tan x =  \frac{\sin x}{\cos x})

We know \sin^2x + \cos^2x = 1 \Rightarrow \sin^2x=1-\cos^2x so we can replace the sin²x in the LHS expression as follows

\frac{\sin^2x}{\cos x} =  \frac{1-\cos^2x}{\cos x} which is the RHS.
7 0
3 years ago
Make (X-12)/(x-8) equal to zero <br><br> A)-2<br> B)-8<br> C)2<br> D)8
nevsk [136]

Answer:

x=12 makes (X-12)/(x-8) equal to zero

x=8 makes (X-12)/(x-8)  undefined

Step-by-step explanation:

(x-12)/(x-8) = 0

The  first step is to multiply each side by x-8

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This cancels the denominator.  x≠ 8 because the denominator would equal 0 and then it becomes undefined.

x-12 = 0

Add 12 to each side

x-12+12 = 0+12

x = 12


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Answer:

x3 would be the answer. the next 3 numbers would be 486, 1458, and 4374

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4 years ago
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Find the surface area of this composite solid.
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