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3 years ago

What is 16,52,76 in a gcf

Mathematics

2 answers:

slamgirl [31]3 years ago

8 0

16: 1,2,4,8,16

52: 1,2,4,13,26,52

76: 1,2,4,19,38,76

So therefore your "GCF" ➡ is'4' (:

Vlada [557]3 years ago

4 0

The greatest common factor is 4

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How do you find the Area of a pentagon

Morgarella [4.7K]

Answer:

Area of a regular pentagon = pa/2, where p = the perimeter and a = the apothem. If you don't know the perimeter, calculate it from the side length: p = 5s, where s is the side length.

Step-by-step explanation:

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2 years ago

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-32x + 45 – 7 (2x – 9) = 101

Evgesh-ka [11]

Answer:

$x = \frac{7}{46}$

Step-by-step explanation:

-32x+45-7(2x-9)=101

parenthesis first

-32x+45-14x+63=101

just combine like terms

-46x+108=101

minus 108 both sides

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3 years ago

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−5x−9y=3 plus 5x−9y=-2

Murrr4er [49]

Answer:

-18y=1

Step-by-step explanation:

Sorry if this is wrong, I was just guessing...

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3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

An evergreen nursery usually sells a certain shrub after 7 years of growth and shaping. The growth rate during those 7 years is

neonofarm [45]

Answer:

(a) $h(t)=\frac{1.3t^2}{2} + 2t +17$

(b)62.85cm

Step-by-step explanation:

The growth rate of the shrub is given as:

$\frac{dh}{dt} = 1.3t + 2$

Where t=time in years, h=height in centimeters

(a)First, we solve for the height h(t) by integrating.

$\int \frac{dh}{dt} dt= \int (1.3t + 2)dt\\h(t)=\frac{1.3t^2}{2} + 2t +C, $ C a constant of Integration$\\$We sunstitute the initial value to find the value of C$\\$When t=0, h=17cm$\\17=C\\Therefore:\\h(t)=\frac{1.3t^2}{2} + 2t +17$

(b)The shrub are sold after 7 years of growth. Therefore, we determine the value of h(t) when t=7 years.

$h(t)=\frac{1.3t^2}{2} + 2t +17\\h(7)=\frac{1.3*7^2}{2} + 2(7) +17\\=31.85+14+17\\h(7)=62.85cm$

The Shrubs are 62.85cm tall when they are sold.

4 0

3 years ago