Using Pythagorean theorem, the student walked 53.58 meters more compared to the total displacement from the starting point.
If a student walks 100 meters north, then 100 meters west, then the path he travels resembles the sides of a right triangle (see attached photo).
Using Pythagorean theorem, we can solve for the total displacement from the starting point to the end point.
c^2 = a^2 + b^2
where c is the total displacement from the starting point to the end point
a is the distance he walks up north
b is the distance he walks to the west
c^2 = 100^2 + 100^2
c^2 = 10,000 + 10,000
c^2 = 20,000
c = 141.42 meters
Comparing the total distance the student walked and the total displacement from the starting point to the end point by subtraction.
100 meters + 100 meters - 141.42 meters = 53.58 meters
Learn more about Pythagorean Theorem here: brainly.com/question/343682
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Hello,
If the teacher has 1/2 of an eraser, and she divides it into 2 pieces to give 1 to each of her students, she gives (1/2) / 2 = (1/2) * (1/2) = 1/4 of the eraser to each student.
Each student takes home 1/4 of the eraser.
Hope this helps!
Answer:
x = 0, 1, -4
Step-by-step explanation:
You can look at the graph where the equation intersects the x-axis.