3 years ago

4sqrt(8)-6sqrt(18) solve the equations

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

What is a formula for the nth term of the given sequence?<br> 36, 24, 16...

SpyIntel [72]

Answer:

The formula to find the nth term of the given sequence is 54 · $\frac{2}{3} ^{n}$

Step-by-step explanation:

The formula for nth term of an geometric progression is :

$a_{n} = \frac{a_{1}(r^{n})}{r}$

In this example, we have $a_{1}$ = 36 (the first term in the sequence) and

r = $\frac{2}{3}$ (the rate in which the sequence is changing).

Knowing what the values for r and $a_{1}$ are, now we can solve.

$a_{n} = \frac{a_{1}(r^{n})}{r}$ = $\frac{36 (\frac{2}{3} ^{n}) }{\frac{2}{3} }$ = 54 · $\frac{2}{3} ^{n}$

Therefore, the formula to find the nth term of the given sequence is

54 · $\frac{2}{3} ^{n}$

3 0

3 years ago

What is 1.08 to the power of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="

OlgaM077 [116]

Answer:

$about \: 1.01551$

Step-by-step explanation:

No it isn't, because:

${1.08}^{ \frac{1}{5} } = { \frac{108}{100} }^{ \frac{1}{5} } = { \frac{27}{25} }^{ \frac{1}{5} } = \sqrt[5]{ \frac{27}{25} } = 1.01551$

6 0

3 years ago

A water truck is filling a swimming pool. The equation that represents this relationship is y = 19.75x where y is the number of

Degger [83]

Answer:

Step-by-step explanation:

1. true

2. true

3. true

4. true

5. true

5 0

2 years ago

nicole will rent a car for the weekend. she can choose one of two plans the first plan has an initial fee of $53 and cost an add

faltersainse [42]

Step-by-step explanation:

what's the question??

8 0

2 years ago

Find the value of w-9 given that –3w+5 = 2

melamori03 [73]

Answer:

$-8$

Step-by-step explanation:

Solving for $w$ given the equation, $-3w +5 = 2$ :

$-3w +5 = 2 \\ -3w +5 -5 = 2 -5 \\ -3w = -3 \\ \frac{-3w}{-3} = \frac{-3}{-3} \\ w = 1$

Solving for $w -9$ when $w = 1$

$1 -9 \\ -8$

3 0

2 years ago