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aalyn [17]
1 year ago
11

A student walked 100 meters north, then 100 meters west. how many more meters did the student walk compared to their total displ

acement from their starting point?
Mathematics
1 answer:
seraphim [82]1 year ago
4 0

Using Pythagorean theorem, the student walked 53.58 meters more compared to the total displacement from the starting point.

If a student walks 100 meters north, then 100 meters west, then the path he travels resembles the sides of a right triangle (see attached photo).

Using Pythagorean theorem, we can solve for the total displacement from the starting point to the end point.

c^2 = a^2 + b^2

where c is the total displacement from the starting point to the end point

a is the distance he walks up north

b is the distance he walks to the west

c^2 = 100^2 + 100^2

c^2 = 10,000 + 10,000

c^2 = 20,000

c = 141.42 meters

Comparing the total distance the student walked and the total displacement from the starting point to the end point by subtraction.

100 meters + 100 meters - 141.42 meters = 53.58 meters

Learn more about Pythagorean Theorem here: brainly.com/question/343682

#SPJ4

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d) Aislinn's average per month on her car is 1,751 miles per month.

<h3>How to find the average speed?</h3>

The average speed is calculated by dividing the total distance traveled by the total time it took to travel that distance. Speed is the rate at which something moves at any given time.

Average speed is the average rate of speed over the course of a journey. Velocity exists as the directional speed of a moving object as an indication of its rate of change in position as observed from a specific frame of reference and measured by a specific time standard.

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7 0
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