Question

The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each defective component has probability 0.60 of being repairable.
a) Find the probability that exactly 15 defective components are produced in a particular day. Round your answer to four decimal places.

Answer 1

Answer:

The probability that exactly 15 defective components are produced in a particular day is 0.0516

Step-by-step explanation:

Probability function : $P(X=x)=e^{-\lambda} \frac{\lambda^x}{x!}$

We are given that The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20.

So,$\lambda = 20$

we are supposed to find the probability that exactly 15 defective components are produced in a particular day

So,x = 15

Substitute the values in the formula :

$P(X=15)=e^{-20} \frac{20^{15}}{15!}$

$P(X=15)=e^{-20} \frac{20^{15}}{15!}$

$P(X=15)=0.0516$

Hence the probability that exactly 15 defective components are produced in a particular day is 0.0516