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4 years ago

How do you work this problem (21÷7)×4= is this correct? 3×4=12

Mathematics

2 answers:

Semenov [28]4 years ago

5 0

(21 ÷ 7) x 4 Divide 21 by 7
3 x 4 Multiply 3 by 4
12

valkas [14]4 years ago

3 0

Yes that's correct 21 divided 7 is three three times 4 is twelve

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Divide the following fractions and reduce to lowest terms 2/3 divided by 4/5

pshichka [43]

Well to divide 2 fraction you first have to find a least common number between the 2 bottom numbers in the fractions, we know automaticall that 15 fits in both the 3 and the 5. now u have to find out what to multiply by each number to get 15, for example what number do you multiply by 3 to get 15?? well it will be 5, so go ahead and multiply it by the fraction (note that what you do in the bottom you have to do in the top) this will give you 10/15, because I multiplied the top and bottom number by 5... lets try the other one what number do you multiply by 5 to get 15?? well it will be 3 so go ahead and multiply that to get 12/15.. now add the top numbers (note that the bottoms always stay the same, you never add or subtract them) when you do you will get 22/15, now you have to see if you can simplify it any further in this case you can't so your final answer is 22/15

Hope this helps

5 0

3 years ago

Nina has prepared the following two-column proof below. She is given that ∠OLN ≅ ∠LNO and she is trying to prove that OL ≅ ON. S

Anit [1.1K]

Step number 3 should really be step number 7, it should be placed after step 4, 5, and 6. The reason is because we won't know that ∠LEO ≅ ∠NEO until after we learn that LE ≅ EN. Because of this, step 3 is in the wrong spot (mistake number one). The secod mistake is that step 7, triangle OLE ≅ triangle ONE is congruent by Angle-Side-Angle (ASA) Postulate, not Side-Angle-Side (SAS) Postulate. It is congruent by ASA because we know that both triangles have equal angles N and L. We also know that the perpendicular bisector creates a 90° angle. So m∠LEO = 90° and ∠NEO = 90°. Therefore, we already have 2 congruent angles in both of the triangles. We also learn that line LE ≅ EN based on the definition of a perpendicular bisector, so we have know one that one side of each triangle is congruent. It is ASA and not AAS, because the ASA Postulate states that two angles and one included side of one triangle are congruent to two angles and one included side of another triangle.

7 0

4 years ago

6(X+1) - 3 = 6X - 7<br> need answer asap

Stolb23 [73]

Answer:

No solution

Step-by-step explanation:

There are no values of x that make the equation true; hence making it have no solution.

8 0

3 years ago

Jill and Jack are exercising at a beach. They both start from the car park at one end of the beach. Jill runs at a constant spee

mina [271]

Jack is at (2/3) of the length of the beach (measuring from the point where they started).

<h3>How far along the beach will Jack be when JIll next passes him?</h3>

Let's think that the whole beach is like a line track of length L.

We know that when Jill completes reaches the end (one complete run) Jack only completed half of it.

So in the time that jill covers the distance L, Jack covers a distance of L/2. So the ratio of their speeds is 2:1 (Jill's speed is double of Jack's speed).

At this point, Jill is on the end of the track and Jack is on the middle, so the distance between them is L/2.

Because of the ratios between the speeds, we know that when they meet again, Jill will have covered 2 thirds of that distance, and jack will cover the other third of that distance.

A third of that distance is:

(L/2)/3 = L/6

So, when they meet, Jack is at L/6 of the middle of the beach, which means that Jack is:

L/2 + L/6 = 3L/6 + L/6 = 4L/6 = 2L/3

Jack is at (2/3) of the length of the beach (measuring from the point where they started).

If you want to learn more about distances:

brainly.com/question/4931057

#SPJ1

4 0

2 years ago

Find the area of this triangle<br> 6 cm l<br> 5 cm w

Svetradugi [14.3K]

Answer:

area. of triangle=1/2(l×w)=1/2(6×5)=15cm²

8 0

3 years ago