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Aneli [31]
3 years ago
6

Mr. Evans is considering offering a second after-school tutoring session for his math students each week. He records the number

of students who attend his current sessions each week. The results from the last twelve weeks are shown in the dot plot below.
Mathematics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

The correct options are:

Four families said they ate out twice the previous week.

One family said they ate out 5 times the previous week.

The median best represents the data set.

Step-by-step explanation:

We are given a data set as:

4, 2, 2, 0, 1, 6, 3, 2, 5, 1, 2, 4, 0, 1

On arranging this data set in the frequency table we get:

Number of times they went for dinner    Number of families  

          0                                                          2

          1                                                           3

          2                                                          4

          3                                                           1

          4                                                           2

          5                                                           1

          6                                                            1

Hence, the range of the number line is between 0 to 6.

Also there are 4 dots above 2.

   Hence,  Four families said they ate out twice the previous week.

Also there is one dot above 5.

       Hence,  One family said they ate out 5 times the previous week.

The data set is not symmetrical since the median is 2 and the data points to the left and to the right do not have symmetry.

Hence, the data set is not symmetrical.

Also we know that the median of the data is the central tendency of the data and always best represents the data.

Hence, The median best represents the data set.

Hope it helped u!.... Btw can u plz mark me BRAINLIEST.. If it helped u?

Tysm!

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Helpeoepeoeoeo show work
alukav5142 [94]

<em>IMPORTANT THIGNS TO REMEMBER:</em>

  • Has 20 lb. dog food!
  • Gives dog 1 3/5 everyday!
  • Find how much eaten after 2 days!
  • Find how much is left!

<em>ANSWER:</em>

Dog has eaten 3 1/5 after 2 days!

There is 16 4/5 left in bag!

<em>EXPLANATION:</em>

Since she gives 1 3/5 to her dog everyday and their asking for 2 days you would multiply 1 3/5 × 2 OR add 1 3/5 + 1 3/5

Which would give you 3 1/5

So, the dog has eaten 3 1/5 lb. of dog food in 2 days.

However then, you would subtract 20 lb. - 3 1/5 lb. because there is 20 lb. dog food in all and the dog has eaten 3 1/5 of it. This would give you 16 4/5 lb.

Meaning there is 16 4/5 lb. left in the bag of dog food!

4 0
3 years ago
How would I solve this?
trasher [3.6K]

You had the right idea using the Pythagorean theorem to solve for b.

Problem is for that triangle to work, the 5 and the 2√2 would have to switch places. The length of a leg cannot be larger than the length of the hypotenuse for it to truly be a right triangle.

Pythagorean theorem only works for the right triangles. Only way to "solve this problem would be to bring in complex numbers.

5² + b² = (2√2)²

25 + b² = 2²(√2)²

25 + b² = 4(2)

25 + b² = 8

b² = 8 - 25

b² = - 17

b = √-17

b= (√17i)

Then the problem with THIS is a measurement/distance cannot be negative... which goes against exactly what that complex number i is.

8 0
3 years ago
A blender costs $18 to make and sells for $21.60. find the markup rate.
RSB [31]
$21.60 - $18.00 = $3.60

$3.60 : $18.00 = 0.2

0.2 · 100% = 20%
5 0
3 years ago
32 is 40 percent of what number? A 12.8 B 128 C 114 D 124​
ELEN [110]

Answer: C

.Step-by-step explanation:

it was right for me so if its wrong im sorry :)

5 0
3 years ago
According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
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