Answer:
52 cm²
Step-by-step explanation:
First, we find the area of the bottom rectangle. We see it's 4 high and 10 wide, so 4x10 is 40. Then, we see that the small figure in the top right has a height of 4 and width of 3, so 4x3 = 12, add those and you get 52.
Answer:
P = 6x +4
Step-by-step explanation:
Use the given values in the formula for the perimeter of a rectangle:
P = 2(L +W)
__
You have ...
L = 2x +4
W = x -2
So, the perimeter is ...
P = 2((2x +4) +(x -2)) = 2(3x +2)
P = 6x +4
The perimeter of the rectangle is 6x+4.
Answer:
The solution set is the empty set.
Step-by-step explanation:
{x | x < 2} is the set of all numbers less than 2. This means x can take values such as 1.99, 0, -2000 and so on. That is, all values less than 2.
{x | x ≥ 2} is the set of all numbers equal to or greater than 2. This means x can take values such as 2, 2.1, 5000, and so on. That is, 2 or any value greater than 2.
Since there is no sign between the two sets, the question is asking for the intersection between these two sets. That is, what elements are common to these two sets? As we can see, the two sets don't have any common element. Hence, their intersection is the empty set.
(Note that the union of these two sets would be the set of all real numbers as that includes all elements from either set).
This is 6P4
the number of permutations of 4 from 6. 6! / 2!
= 6*5*4*3* 2 / 2 = 360
