Choose the definition for the function. please help me
2 answers:
9514 1404 393
Answer:
A
Step-by-step explanation:
It is usually sufficient to look at one section of the graph to answer a question like this. Often the best choice is the section that has a solid dot at the end of the curve. Here, that is the right section.
The left end of the right section is at x=-2, so that part of the function is defined for x ≥ -2. The line to the right has a positive slope, so the coefficient of x will be positive.
Only one answer choice has a positive x-coefficient for x ≥ -2.
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The right answer is Option C.
Step-by-step explanation:
Given equations are;
-2x+4y=17 Eqn 1
3x-10y= -3 Eqn 2
Adding Eqn 1 and Eqn 2;
The right answer is Option C.
Keywords: linear equations, addition
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Answer:
C.
Step-by-step explanation:
Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.
So, if we're taking f/g, we have:
4x - 3 makes up our denominator, the bottom part of the fraction. So
4x - 3 = 0
4x = 3
x = 3/4
So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.
(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:
If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)
Step-by-step explanation:
For equation N°2
Solving algebraically:
(Sum x on both sides of the equation)
Resolving graphically:
x = -2 --------- - (- 2) -3 = -1 pto (-2, -1)
x = -4 ---------- - (- 4) -3 = 1 pt (-4.1)
x = -3 --------- - (- 3) -3 = 0 pt (-3.0) Solution
The graphic is shown in the attached image. The red dot in the graph represents the solution
For equation N° 4
Solving algebraically:
(Sum -3 on both sides of the equation)
(divided by 9 on both sides of the equation)
(simplifies the fraction)
Resolving graphically:
x = 1 --------- 9 (1) +3 = 12 pt (1.12)
x = -1 --------- 9 (-1) +3 = -6 pto (-1, -6)
x = -1 / 3 -------- 9 (-1/3) +3 = 1 pt (-1 / 3.0) Solution
The graphic is shown in the attached image. The red dot in the graph represents the solution
For equation N°. 6.
Solving algebraically:
(Sum -4x on both sides of the equation)
The equation is not met, the x are eliminated, therefore, it has solution
For equation N°. 8
Solving algebraically:
(Sum 6x on both sides of the equation)
The x are eliminated, 3 is not equal to 5, the equality is not met. The equation has no solution.
