Question

The length of a rectangle is 10 inches longer than the width. The perimeter is 56 inches. Find the length and the width of the rectangle

Answer 1

Answer:

$Length=19\,inches\\\\Width=9\,inches$

Step-by-step explanation:

Let, the length of the rectangle be 'L',

Width of the rectangle be 'W'

$L=(W+10)\,inches$

Perimeter of the rectangle= $56\,inches$

Perimeter of the rectangle= $2(Length+Width)$

                     $56=2(W+10+W)\\\\\dfrac{56}{2} =W+10+W\\\\28=2W+10\\\\28-10=2W\\\\18=2W\\\\W=\dfrac{18}{2}\\\\ W=9\,inches$

As,

     $L=(W+10)\,inches$

     $L=9+10\\\\L=19\,inches$

$Length=19\,inches\\\\Width=9\,inches$