Ask question

Ask question

All categories

3 years ago

10

The length of a rectangle is 10 inches longer than the width. The perimeter is 56 inches. Find the length and the width of the r

ectangle

1 answer:

goldfiish [28.3K]3 years ago

7 0

Answer:

$Length=19\,inches\\\\Width=9\,inches$

Step-by-step explanation:

Let, the length of the rectangle be 'L',

Width of the rectangle be 'W'

$L=(W+10)\,inches$

Perimeter of the rectangle= $56\,inches$

Perimeter of the rectangle= $2(Length+Width)$

$56=2(W+10+W)\\\\\dfrac{56}{2} =W+10+W\\\\28=2W+10\\\\28-10=2W\\\\18=2W\\\\W=\dfrac{18}{2}\\\\ W=9\,inches$

As,

$L=(W+10)\,inches$

$L=9+10\\\\L=19\,inches$

$Length=19\,inches\\\\Width=9\,inches$

You might be interested in

Please help me with this geometry question !!!

Inessa05 [86]

Answer:

see explanation

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 90°

a point (x, y ) → (- y, x ), thus

P(1, - 1 ) → P'(1, 1 )

Q(3, - 2 ) → Q'(2, 3 )

R(3, - 4 ) → R'(4, 3 )

8 0

3 years ago

Felipe is planning a party. He has $50.00 to spend on sandwiches that cost $2.50 per person, $25.00 to spend on drinks that cost

Maksim231197 [3]

Answer:

Its B

Step-by-step explanation:

In all, he has $100 to spend since $50+$25+$25=$100. We have x people coming and he has to spend $2.50, $1.50, and $3.00 per person, respectively. The phrase "per person" indicates we must multiply, so we have to multiply each value by "x." To find out how much money he has left, we must subtract. All of this put together is 100-(2.50x+1.50x+3.00x). Add the like terms and you get 7x. Your final expression would be 100-7x, which is answer choice b.

3 0

3 years ago

Read 2 more answers

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago

for every girl taking classes at the martial arts schools there are 3 boys who are taking classes at the school. if there are 23

Yuliya22 [10]

You have to be very careful how you set this up. For every girl (who counts as 1) there are 3 boys (who count as 3). The total number in the proportion is 3 + 1 =4. You are given a total, but that is both boys and girls. That's why you need the 4.

3/4 = x / 236 Cross multiply

4x = 3 * 236

4x = 708 Divide by 4

x = 708/4

x = 177

There are 177 boys at the school and 236 - 177 = 59 girls.

3 0

3 years ago

A cat chases a mouse. The cat is originally 4 feet behind the mouse, which is running in the same direction along the same route

Darya [45]

The cat will take 0.8 seconds to catch up with the mouse

Step-by-step explanation:

Given:

The distance between the cat and the mouse = 4 feet

cat's speed = 17 feet per second.

mouse's speed = 12 feet per second

To Find:

how long will it take the cat to catch up with the mouse = ?

Solution:

We know that

distance = speed x time

Rewriting the equation for time we get

time = $\frac{distance }{speed}$

now we know that distance is 4 feet

and the speed is 17 -12 = 5 feet per second

Thus the time is

= $\frac{4}{5}$

= 0.8 seconds

4 0

3 years ago