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2 years ago

15

Suppose that it costs $16 to place a classified advertisement in the newspaper, plus $6 for each line. Then the cost to place an

ad x lines long is given by y dollars,
where y = 6x + 16.
Express as an ordered pair the fact that a 12 line ad costs $88.

1 answer:

s344n2d4d5 [400]2 years ago

3 0

2/5.85.0

4508.9865.0854

5651856123.

78956412

564=.000

85623.08

856312.00

9896531791.08885

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Rewrite each fraction in simplest form using the GCF of the numerator and denominator.

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Answer:

$\sf 6. \quad \dfrac{7}{10}$

$\sf 7. \quad \dfrac{5}{17}$

Step-by-step explanation:

<h3><u>Question 6</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

42 = 2 × 3 × 7
60 = 2 × 2 × 3 × 5

42 and 60 share one 2 and one 3 in common.

Multiply them together to get the GCF: 2 × 3 = 6.

Therefore, 6 is the GCF of 42 and 60.

Divide the numerator and the denominator by the found GCF:

$\implies \sf \dfrac{42 \div 6}{60 \div 6}=\dfrac{7}{10}$

<h3><u>Question 7</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

80 = 2 × 2 × 2 × 2 × 5
272 = 2 × 2 × 2 × 2 × 17

80 and 272 share four 2s in common.

Multiply them together to get the GCF: 2 × 2 × 2 × 2 = 16.

Therefore, 16 is the GCF of 80 and 272.

Divide the numerator and the denominator by the found GCF:

$\implies \sf \dfrac{80 \div 16}{272 \div 16}=\dfrac{5}{17}$

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Answer:

Getting through ratio method

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Step-by-step explanation:

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Yuri [45]

Hence, the required inequality is x+y≤4, 7x+4y≤1150

<h2>What is inequality?</h2>

inequality, In mathematics, a statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

<h3>How to solve?</h3>

Let x be the number of adults and y be the number of campers.

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to learn more about inequality: brainly.com/question/16562548

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