Well, we can denote L and W for the length and width respectively. Lets say the A is the area, we have: 1. A=(L × W) as well as 2. 2(L+W)=400. We rearrange the second equation to get 3. W=200-L. From this, we can see that 0<L<200. Substitute the third equation into the first to get A=(200L-L²). put this formula into the scientific calculator and you will find a parabola with a maximum. That would be the maximum area of the enclosed area. Alternatively, we can say that L is between 0 and 200 when the area equals 0. (The graph you find will be area against length). As the maximum is generally found halfway, we substitute 100 into the equation and we end up with 10000.
Hope this helps.
Circle A is missing, so i have attached it.
Answer:
∠XYZ = 35°
Step-by-step explanation:
We want to find the angle ∠XYZ in the image attached.
To solve that, we will use the formula in the theorem for angle formed by secants or tangents. Thus;
∠XYZ = ½(arc WZ - arc XZ)
From the image, arc WZ = 175° and arc XZ = 105°
Thus;
∠XYZ = ½(175 - 105)
∠XYZ = ½(70)
∠XYZ = 35°
Answer:
C
Step-by-step explanation:
First of all their is an easier way solving this 2l/ + l^2
but how you need it is c because the base is 100 and each face is 40 how 10x8=80 80/2=40
3,989.237
A thousandth = 1/1000 = 0.001
Round 4th decimal place = 5
5 and over is rounding up and under 5 rounds down so it would be 3,989.237
