Algebra PLS HELP!!!!!!!!!!!!!
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The question is incomplete, here is the complete question:
Given a radius of 9 inches intercepted by the central angle 60°. Estimate the length of arc 'S' to the nearest hundredth.
<u>Answer:</u> The arc length of the circle is 9.42 inches
<u>Step-by-step explanation:</u>
To calculate the length of the arc, we use the formula:
where,
S = arc length = ?
r = radius of the circle = 9 inches
= central angle = 60°
Putting values in above equation, we get:
Hence, the arc length of the circle is 9.42 inches
Answer:
Step-by-step explanation:
An isosceles triangle has two equal sides and the two opposite angles to the sides to be equal.
Given that; RP = RS, RQ and PS are common,
RP = SQ (opposite sides of parallelogram RPQS)
PQ = RS (opposite sides of parallelogram RPQS)
ΔRPS = ΔQPS (congruence property)
Thus comparing triangles PQR and SQR,
=
(similarity property)
<PRS = <PRQ + <SRQ (bisection of included <PRS)
<PQS = <PQR + <SQR (similatity property to <PRS)
=
(congruence property)
But, SRQ = PQR
So that;
Therefore by Side-Angle-Side (SAS), the required additional fact is: