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2 years ago

HELP ME PLZ ILL GIVE U EXTRA POINTS

Mathematics

1 answer:

likoan [24]2 years ago

6 0

Answer:

10 32 -9

10 -13 18

-9 -8 11

hope this helps

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Which equation is represented by the graph?

vladimir2022 [97]

Answer: y = -2x - 5

Step-by-step explanation:

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3 years ago

You're going on a 1211-mile trip, and your car gets about 29 miles per gallon. Gas prices along your route average $3.40. Estima

Vilka [71]

Answer:

Using the estimate:

The car has to go for 1,200 miles but it consumes a gallon of gasoline for every 30 miles. The number of gallons it will need is therefore:

= 1,200 / 30

= 40 gallons

Each gallon costs $3.00 so the total cost is:

= 40 * 3

= $120

Without using the estimate:

The car has to go for 1,211 miles but it consumes a gallon of gasoline for every 29 miles. The number of gallons it will need is therefore:

= 1,211 / 29

= 41.76 gallons

Each gallon costs $3.40 so the total cost is:

= 41.76 * 3.40

= $‭141.98

<em>Using the estimate provides a lower cost of gasoline for the trip. </em>

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2 years ago

What is the recursive rule for the following sequence: -5, -3, -1, 1…

Irina18 [472]

$a_{n}$ = $a_{n-1}$ + 2

So C.

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2 years ago

10 increased by the quotient of a number and 6 is 15

Makovka662 [10]

<h2>Verbal Phrase to Mathematical Phrase</h2><h3>Answer:</h3>

$10 +\frac{n}{6} = 15\\$

<h3>Step-by-step explanation:</h3>

Let that number be $n$ .

The quotient of a number and $6$ is $\frac{n}{6}\\$ .

"Increased" is just another term for "plus (+)" so $10$ increased by The quotient of a number and $6$ is $10 + \frac{n}{6}\\$

And it tells us that it is $15$ so it must be $10 +\frac{n}{6} = 15\\$

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2 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for <em>Angles</em>

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

Solving for <em>Edges</em>

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under <em>two</em> conditions:

One angle and two edges defined, while trying to solve for the <em>third edge</em>
ALL three edges defined

* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

Two angles and one edge defined, while trying to solve for the <em>second edge</em>
One angle and two edges defined, while trying to solve for the <em>second angle</em>
ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

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1 year ago