All categories

3 years ago

Can you put parenthesis inside parenthesis

Mathematics

2 answers:

stealth61 [152]3 years ago

7 0

Yes, you can put parenthesis inside of parenthesis.

Gnoma [55]3 years ago

4 0

Yes you can hope that helps

You might be interested in

Write the number 5267 correct to the nearest hundred.

galben [10]

Answer:

5300.

If you're rounding to the nearest hundred you look at the tens place. If its 5 or over you go up. So in this case we'll raise the 2 to a 5 because 6 is above 5.

4 0

2 years ago

Given that(4,6) is on the graph of f(x) find the corresponding point for the function f(-4x)

Len [333]

Answer:

(-1,6)

Step-by-step explanation:

Given that(4,6) is on the graph of f(x)

f(-4x) means x is multiplied by -4

When x is multiplied by -1 then there will be reflection over y axis

We multiply every point by -1. so multiply the x values of the given point (4,6) by -1

New point is (-4,6)

If any number is multiplied with x then there will be a horizontal compression or stretch.

4 is multiplied with x , so there will be horizontal compression because 4 is greater than 1

To get new point, we divide the x values by 4 for compression

we already got (-4,6) after multiplying by -1

Now we divide the x coordinate -4 by 4 = -1

So corresponding point for the function f(-4x) is (-1,6)

5 0

2 years ago

Is 8:2 greater than 5:1? I need someone to help me clarify if this is correct. Thanks.

kaheart [24]

Answer:

No, 8:2 = 4:1 which is less than 5:1

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

Hence, the theorem that compares both triangles is the SAS theorem

4 0

2 years ago

You brought 1.5 dozen bagels to school. A dozen bagels cost $5.98. You used a coupon that took $1.00 off of the total. How much

shusha [124]

Answer: (7.97)

Step-by-step explanation:

1 dozen = 5.98

.5 dozen = 2.99

5.98+2.99=8.79 8.79- the 1.00 is (7.97)

hope this helps!

3 0

2 years ago