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Drupady [299]
3 years ago
6

In a lab, a scientist is growing bacteria for a study. The scientist begins with a bacteria

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

The growth of the bacteria is in the form of an exponential growth. It is given by the formula:

P(t)=ae^{rt}\\\\where\ t\ is\  the\ number\ of \ hours, P(t)\ is\ the \ population\ at\ t\ hours\\\and\ a=population\ at\ start

At 2 hours, the population is 62 cells, hence:

P(2)=ae^{2r}\\\\62=ae^{2r}\ \ .\ \ .\ \ .\ (1)

After another 2 hours (4 hours), the population is 1 million:

P(4)=ae^{4r}\\\\1000000=ae^{4r}\ \ .\ \ .\ \ .\ (2)\\\\Divide \ equation\ 2\ by\ equation\ 1:\\\\\frac{1000000}{62}=\frac{ae^{4r}}{ae^{2r}} \\\\16129=e^{2r}\\\\ln(e^{2r})=ln(16129)\\\\2r=9.688\\\\r=4.844

Put r = 4.844 in equation 1

62=ae^{2*4.844}\\\\62=16129a\\\\a=0.003844

P(t)=0.003844e^{4.844t}\\\\at \ start,t=0\\\\P(0)=0.003844

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Step-by-step explanation:

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In elimination, we want both equations to have the same form and like terms to be lined up.  We have that.  We also need one of the columns with variables to contain opposites or same terms. Neither one of our columns with the variables contain this.  

We can do a multiplication to the second equation so that the first terms of each are either opposites or sames. It doesn't matter which.  I like opposites because you just add the equations together. So I'm going to multiply the second equation by -3.

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