Triangle XYZ has vertices X(2,4), Y(3,4) and Z(3,8). Suppose you reflect this across the y-axis, then dilate it with a scale fac
tor of 2 with the origin as the center of dilation. What are the coordinates of the resulting triangle X″Y″Z″? answers: A) X″(–4,8), Y″(–6,8), Z″(–6,16) B) X″(2,–4), Y″(3,–4), Z″(3,–8) C) X″(–2,4), Y″(–3,4), Z″(–3,8) D) X″(4,–8), Y″(6,–8), Z″(6,–16)
Y = x + 8....the slope here is 1. A parallel line will have the same slope.
y = mx + b slope(m) = 1 (2,16)....x = 2 and y = 16 now we sub into the formula and find b, the y int 16 = 1(2) + b 16 = 2 + b 16 - 2 = b 14 = b so ur equation is : y = x + 14 <==