Yes you always do.
eg x - 2 = 8
x - 2 + 2 = 8 + 2
x = 10
if we plug x = 10 into the original equation we se that this fits:-
10 - 2 = 8
If the problem was written x + 4x. We would know to add like the coefficients together and get 5x same thing with the radicals.
C=5.20/8=$0.65
1 $0.65
10 $6.50
18 $11.70
24 $35.10
Hope this helps. Mark as branliest tq