Answer:8a-28b+15c
Step-by-step explanation:
Answer:
y_c = 2 + 10*x
Step-by-step explanation:
Given:
y'' = 0
Find:
- The solution to ODE such that y(0) = 2, y'(0) = 10
Solution:
- Assuming a solution y = Ce^(mt)
So, y' = C*me^(mt)
y'' = C*m^2e^(mt)
- Back substitute into given ODE, we get:
y'' = C*m^2e^(mt) = 0
e^(mt) can not be equal to zero
- Hence, m^2 = 0
m = 0 , 0 - (repeated roots)
- The complimentary function for repeated roots is:
y_c = (C1 + C2*x)*e^(m*t)
y_c = C1 + C2*x
- Evaluate @ y(0) = 2
2 = C1 + C2*0
C1 = 2
-Evaluate @ y'(0) = 10
y'(t) = C2 = 10
Hence, y_c = 2 + 10*x
C and D
150(1+2.5) and 150(3.5)
20.31 is the same as 20.310
So, 20.301 is less than 20.310
Answer:
166 square units
Step-by-step explanation:
Let’s find the area of the shapes that in the net.
First, we can see two of the triangles have a base of 2 and a height of 13. The formula for surface area of a triangle is bh÷2. (13x2)÷2=13. Since there are two triangles, we multiply 13 by 2 and get <u><em>26</em></u>.
Second, we can see two of the triangles have a base of 10 and a height of 12. (10x12)÷2=<u>60.</u> Since there are two triangles, we multiply 60 by 2 and get <u>120</u>.
Third, we can see a rectangle has a base of 10 and a height of 2. The formula for surface area of a rectangle is bh. 10x2=<u>20</u>.
Last, we add up all the areas:
20+120+26=166.