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bezimeni [28]
3 years ago
14

Through any three points there __________ exists exactly one line

Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0
Through any three points there never exists exactly one line. Hope this helps! Any questions about my answer feel free to ask in the comments below!
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1.2n+12!/n-1!<br><br><br><br> 2. 4n+3!/2n+1!
Naddik [55]
Are you sure there is no bracket in the denominators (n-1)! if not then the answer is:

1) 2n + 12!/2n -1 ===> 2n + (479,001,600)/n -1 or (2n²-n+12!)/n
2) 4n+3!/2n +1! ====>4n +3/n +1
3 0
3 years ago
Monica deposits $300 into a savings account that pays a simple interest rate of 4.2% paul deposits $400 into a savings account t
dalvyx [7]

Answer:

Paul earned $2.6 more interest than Monica.

Step-by-step explanation:

Giving the following information:

Monica:

Initial investment= $300

Interest rate= 4.2%

Paul:

Initial investment= $400

Interest rate= 3.8%

<u>To calculate the income earned, we need to use the following formula:</u>

I= P*r*t

P= principal

r= interest rate

t= time

Monica:

I= 300*0.042*1= $12.6

Paul:

I= 400*0.038*1= $15.2

Paul earned $2.6 more interest than Monica.

7 0
3 years ago
Help meee will give brainlist
Lilit [14]
1. 0
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5 0
3 years ago
Read 2 more answers
3. Give the domain of y= √6-X using set builder notation.​
Molodets [167]

Answer:

{x | x ≤ 6}

Step-by-step explanation:

Given

y = √(6 - x)

Required

Determine the domain

We start by setting 6 - x to ≥ 0.

i.e.

6 - x ≥ 0

Add x to both sides

6 - x + x ≥ 0 + x

6 ≥ x

This can be rewritten as

x ≤ 6

Using set builder, the above van be represented as: {x | x ≤ 6}

8 0
3 years ago
You are going to make “words” using the letters in the word WHISKAS. a) How many seven-letter words can you make? b) How many se
nalin [4]

Hey there! I'm happy to help!

PART A

When we say words, we don't really mean words. We just mean how many different ways we can arrange the letters. We could make a word like Hiskasw and that would work.

We have six different letters: w, h, i, s, k, and a. We have two s's and this will be very important when finding these permutations.

The first thing we do is take the number of letters and find its factorial. In this case, it is seven, so we have 7×6×5×4×3×2×1=5040.

But, this is not how many combinations there are, because we have two s's, and since they are the same many of our combinations are actually identical, but the s's are just switched. So, we take the number of s's (2) and we factorial it, which just still equals two, and then we divide our first factorial by that.

5040/2=2520

There are 2520 ways you can arrange the word WHISKAS.

PART B

Let's think of the seven letter slots in the word. It doesn't matter where you place one of the S's, but a slot next to the first S you place only has one choice of letter, which is another S to make it adjacent. This means that one  specific slot is required to have an S. If we start off filling in our required one with an S, we have six letters left to fill in our other slots, which will give us a result of 6!, which is 720 seven-letter words.

PART C

Now, we have to have A be the first term and H be the last. If we think of the seven letter slots, we have only one choice on the first one, which is A, and only one choice on the last one, which is H. This leaves us with 5! or 120 possibilities, but we also have to divide by two because we have two S's, so there are 60 seven-letter words you can make if the words must begin with A and end with H.

Have a wonderful day!

4 0
3 years ago
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