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RoseWind [281]
3 years ago
14

Given the following three points, find by hand the quadratic function they represent.

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0

Answer:

The equation is;

f(x) = -2·x² + 5·x - 1

Step-by-step explanation:

The general form of a quadratic equation  or function f(x) is, f(x) = y = a·x² + b·x + c

Given that the points representing the quadratic function are;

(-1, -8), (0, -1), (1, 2) which  are of the form (x, y)

When x = -1, f(x) = y = -8

Plugging in the above values into the general form of a quadratic function, we have;

-8 = a·(-1)² + b·(-1) + c = a - b + c

-8  = a - b + c.........................(1)

When x = 0, y = -1, we have;

-1 = a·(0)² + b·(0) + c = c

c = -1.......................................(2)

When x = 1, y = 2, which gives;

2 = a·(1)² + b·(1) + c = a + b + c

2 = a + b + c........................(3)

Adding equation (1) to equation (3), we have;

-8 + 2 = a - b + c + a + b + c

-8 + 2 = 2·a + 2·c

From equation (2) c = -1, we get;

-8 + 2 = -6 = 2·a + 2·c = 2·a + 2 × (-1)

-6 = 2·a - 2

-4 = 2·a

a = -2

From equation (3), we have

2 = a + b + c

Substituting the values of a, and c gives;

2 = -2 + b - 1

b = 2 + 2 + 1 = 5

b = 5

The equation is therefore;

f(x) = -2·x² + 5·x - 1.

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The ratio of girls to boys competing at a gymnastics competition was 2 to 1 there were 75 kids participating in the competition.
skad [1K]

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Step-by-step explanation:

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8 0
3 years ago
Triangle FGH with vertices F(6,6), G(8,8), and H(8,3): (a) Reflection: in the line x = 5 (b) Translation: (x,y)→ (x - 7, y - 9)
irakobra [83]

(a) The vertices after the reflection in the line x = 5 are F'(4,6) , G'(2,8) , H'(2,3) .

and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .

In the question a triangle FGH with vertices F(6,6) , G(8,8) and H(8,3) is given

Part (a)

the rule for reflection of point (x,y) by the line x = p  is

(x,y) → (2×p - x , y)

reflection by the line x = 5 ,

we get

the vertices as

F'(2×5-6,6) = (4,6)

G'(2×5-8,8) = (2,8)

H'(2×5 - 8 ,3) = (2,3)

Part (b)

the rule of translation is given as (x,y)→ (x - 7, y - 9)

So , the vertices after translation are

F''(6-7 , 6-9) = (-1,-3)

G''(8-7,8-9) = (1,-1)

H''(8-7,3-9) = (1,-6)

Therefore , (a) The vertices after the reflection in the line x = 5 are F'(4,6)

G'(2,8) , H'(2,3) .

and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .

Learn more about Translation here

brainly.com/question/3456459

#SPJ1

7 0
1 year ago
Find the exact value of tan(165°) using a difference of two angles
Katyanochek1 [597]

Answer:  -2+\sqrt{3}

=========================================================

Work Shown:

Apply the following trig identity

\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\

Now let's rationalize the denominator

\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\

----------------------

As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.

Or you can note how

\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949

which helps us see that they are the same thing.

Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as \sqrt{3}-2 but it's the same as above.

5 0
3 years ago
Which is f(5) for the function -2x^2+2x-3
sweet-ann [11.9K]

Answer:

f(5)=-43

Step-by-step explanation:

Hope this helps!!!!!!

3 0
4 years ago
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