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s2008m [1.1K]
3 years ago
8

The splitting of a _____ molecule begins the process of glycolysis.

Biology
2 answers:
galina1969 [7]3 years ago
8 0

<u>Answer</u>

Glucose


The splitting of a <u>glucose</u> molecule begins the process of glycolysis.

forsale [732]3 years ago
4 0

Once glycolysis has occured, the splitting of a glucose molecule can begin. Given that, the answer can be no other than glucose.


Answer:


\boxed{\bf~Glucose~starts~splitting~after~glycolysis.}



Hope it helped,


Happy homework/ study/ exam!

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Answer:

\text{Present a flower with one characteristic changed to the normal pollinator. }\text{As a control, present a flower with no characteristics changed to the normal pollinator}

\text{Record any measure of pollination success}

\text{Repeeat for flowers with other characteristics changed}

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Explanation:

The missing information is attached below.

 \text{Present a flower with one characteristic changed to the normal pollinator. }\text{As a control, present a flower with no characteristics changed to the normal pollinator}

For the control, you'll need something you're already familiar with. In this scenario, a normal flower with no changes in characteristics is the best control. And if no data is accessible, you still have data on the success rate of a typical flower, which can be used as a guideline. And, for the initial configuration, you can only adjust one characteristic so it would be easier to maintain track of and analyze the data gathered.

\text{Record any measure of pollination success}

Since the aim of your experiment is to examine the influence of flower characteristics on pollination performance, you should keep track of the active pollination events. To have more accurate results, this would require listing the total number of plants that were to be pollinated.

\text{Repeeat for flowers with other characteristics changed}

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\text{Analyze the data to determine which altered characteristics affect pollination }<u />\text{success the most. This characteristic will be the result of the experiment.}<u />

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