3 years ago

Whats the equation of a line perpendicular to y= 0.25x-7 and passes through (-6,8)

1 answer:

8 0

$y - 8 = 4(x + 6)$
The slope perpendicular to 1/4 or .25 is 4.
Then you would use point slope form to write the equation.
Then you could simiplify the equation to y=4x+32.

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8(-b+4)= idk what the answer is please help

iren [92.7K]

Answer:

-8b+36 is the answer.

Step-by-step explanation:

=8(-b+4)

Opening brackets to simplify

=8✖️(-b)+8✖️4

=-8b+36 is the answer.

Hope this will help you :)

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Slav-nsk [51]

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How do I solve this question?

Sati [7]

Answer:

m=2 and n=3

Step-by-step explanation:

Step :-

Given $[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

using algebraic formula $(a^m)^n= a^{mn}$

now

$2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}$

now equating 'x' powers, we get

$x^{mn} = x^{6}$

$mn=6$ ....(1)

now

$y^{2m} = y^{4}$

Equating 'y' powers ,we get

2 m=4

m=2

substitute m= 2 in equation (1)

we get

2 n=6

n=3

verification:-

substitute m=2 and n=3 , we get

$[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

$(2 x^{3} y^2)^2 = 4 x^6 y ^4\\$

$4 x^6 y^4 = 4 x^6 y^4$

both are equating so m= 2 and n=3

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